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2x=x^2+9
We move all terms to the left:
2x-(x^2+9)=0
We get rid of parentheses
-x^2+2x-9=0
We add all the numbers together, and all the variables
-1x^2+2x-9=0
a = -1; b = 2; c = -9;
Δ = b2-4ac
Δ = 22-4·(-1)·(-9)
Δ = -32
Delta is less than zero, so there is no solution for the equation
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